Question

Giải hệ phương trình: \(\hept{\begin{cases}2x^2+y^2-3xy-4x+3y+2=0\\\sqrt{x^2-y+3}+\sqrt{y-x+1}=2\end{cases}}\)

Answer 1

Ta có : \(\hept{\begin{cases}2x^2+y^2-3xy-4x+3y+2=0\\\sqrt{x^2-y+3}+\sqrt{y-x+1}=2\end{cases}}\)

Xét phương trình đầu : \(2x^2+y^2-3xy-4x+3y+2=0\)

\(\Leftrightarrow\left(2x^2-xy-2x\right)+\left(-2xy+y^2+2y\right)+\left(-2x+y+2\right)=0\)

\(\Leftrightarrow x\left(2x-y-2\right)-y\left(2x-y-2\right)-\left(2x-y-2\right)=0\)

\(\Leftrightarrow\left(2x-y-2\right)\left(x-y-1\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}2x-y-2=0\\x-y-1=0\end{cases}}\)

Từ đó thay y bởi x vào pt còn lại để tìm nghiệm.

Answer 2

giúp mình câu khác với

Answer 3

khó thật đấy

Answer 4

khó quá ko hiểu để mình giúp bạn bài khác nhé àhihihihihihihihihihihihihihihihihihihihihihi

Answer 5

úi giòi

Answer 6

uuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuuu

Answer 7

qqqmhyjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjfzvSZGZAFDHjvjjqwertyuiopasdfghjklzxcvbnmmmmmmmmnbvcxzlkjhgfaqwertyuiopoiuytrewqs

Answer 8

kkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkkoooooooooooo

Answer 9

O Hen-ri là nhà văn tài năng của nước nào?

Answer 10

đầu buồi ăn cức nhớ

Answer 11

I dont Know

Answer 12

ủiókouiiyiguu8

Answer 13

Viết từ 7-10 câu tả về người lao động trí óc .

Answer 14

what tờ fuck

Answer 15

Mọi người nói gì thế

Answer 16

Tao éo biết nha