\(a,M=3x^2+2xy+y^2+1-2x^2-2xy-y^2\\ =\left(3x^2-2x^2\right)+\left(2xy-2xy\right)+\left(y^2-y^2\right)+1\\ =x^2+1\)
Vậy \(M=x^2+1\)
\(b,\)
\(M=17\\ \Leftrightarrow x^2+1=17\\ \Leftrightarrow x^2=16\\ \Rightarrow x^2=4^2\left(x>0\right)\\ \Rightarrow x=4\)
Vậy \(x=4\)