`1/4+1/3:(2x-1)=-5`
`1/3:(2x-1)=-5-1/4=-21/4`
`2x-1=1/3:(-21/4)=-4/63`
`2x=-4/63+1=59/63`
`x=59/63:2=59/126`
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`3(3x-1/2)^3+1/9=0`
`3(3x-1/2)^3=-1/9`
`(3x-1/2)^3=-1/27`
`(3x-1/2)^2=(-1/3)^3`
`3x-1/2=-1/3`
`3x=-1/3+1/2=1/6`
`x=1/18`
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`3(x-1/2)-5(x+3/5)=-x+1/5`
`3x-3/2-5x-3=-x+1/5`
`3x-5x+x=1/5+3/2+3`
`-x=47/10`
`x=-47/10`
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`(x+1/2)(2/3-2x)=0`
`@TH1:x+1/2=0=>x=-1/2`
`@TH2:2/3-2x=0=>2x=2/3=>x=1/3`
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`2/3x-1/2x=5/12`
`(2/3-1/2)x=5/12`
`1/6x=5/12`
`x=5/2`
dòng thứ 4 đk á:v
\(\left(x+\dfrac{1}{2}\right)\left(\dfrac{2}{3}-2x\right)=0\)
=> \(\left\{{}\begin{matrix}x+\dfrac{1}{2}=0\\\dfrac{2}{3}-2x=0\end{matrix}\right.\)
=> \(\left\{{}\begin{matrix}x=0-\dfrac{1}{2}\\2x=\dfrac{2}{3}\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{2}{3}:2=\dfrac{1}{3}\end{matrix}\right.\)
Vậy \(S=\left\{-\dfrac{1}{2};\dfrac{1}{3}\right\}\)
\(\dfrac{1}{4}+\dfrac{1}{3}:\left(2x-1\right)=-5\\ \dfrac{1}{3}:\left(2x-1\right)=-\dfrac{21}{4}\\ 2x-1=-\dfrac{4}{63}\\ 2x=\dfrac{59}{63}\\ x=\dfrac{59}{126}\)
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\(3\left(3x-\dfrac{1}{2}\right)^3+\dfrac{1}{9}=0\\ 3\left(3x-\dfrac{1}{2}\right)^3=-\dfrac{1}{9}\\ \left(3x-\dfrac{1}{2}\right)^3=-\dfrac{1}{27}\\ \left(3x-\dfrac{1}{2}\right)^2=\left(-\dfrac{1}{3}\right)^3\\ 3x-\dfrac{1}{2}=-\dfrac{1}{3}\\ x=\dfrac{1}{12}\)
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\(\left(x+\dfrac{1}{2}\right)\left(\dfrac{2}{3}-2x\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=0\\\dfrac{2}{3}-2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=\dfrac{1}{3}\end{matrix}\right.\)
