`a)` \(\dfrac{2}{9}+\dfrac{5}{7}\times\dfrac{14}{3} =\dfrac{2}{9}+\dfrac{10}{3}=\dfrac{2}{9}+\dfrac{30}{9}=\dfrac{32}{9}\)
`b)` \(\dfrac{7}{2}+\dfrac{6}{7}:3=\dfrac{7}{2}+\dfrac{6}{7}\times\dfrac{1}{3}=\dfrac{7}{2}+\dfrac{2}{7}=\dfrac{49}{14}+\dfrac{4}{14}=\dfrac{53}{14}\)
Đúng 2
Bình luận (0)
a, \(\dfrac{2}{9}+\dfrac{5}{7}x\dfrac{14}{3}=\dfrac{2}{9}+\dfrac{70}{21}=\dfrac{32}{9}\)
b, \(\dfrac{7}{2}+\dfrac{6}{7}:3=\dfrac{7}{2}+\dfrac{6}{7}:\dfrac{3}{1}=\dfrac{7}{2}+\dfrac{6}{21}=\dfrac{55}{21}\)
Đúng 0
Bình luận (0)