Ta có:\(\dfrac{1}{3}\)=\(\dfrac{1x2}{3x2}\)=\(\dfrac{2}{6}\) ; \(\dfrac{2}{3}\)=\(\dfrac{2x2}{3x2}\)=\(\dfrac{4}{6}\)
\(\dfrac{2}{6}\) < X < \(\dfrac{4}{6}\)
X=\(\dfrac{3}{6}\)=\(\dfrac{1}{2}\)
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\(b=\left\{\dfrac{1}{2};\dfrac{2}{5}\right\}\)
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