a) `1/7+(-4/7) = (1-4)/7=-3/7`
e) `-1/16-1/15 = -15/(16.15) - 16/(15.16)`
`=(-15-16)/(16.15)`
`=-31/240`
\(a.\dfrac{1}{7}+\dfrac{-4}{7}=\dfrac{-3}{7}\\ b.\dfrac{-1}{16}-\dfrac{1}{15}=\dfrac{-31}{240}\)
a) 1/7+-4/7=-3/7
b)-1/16-1/15=-15/240-16/240=-31/240
a) \(\dfrac{1}{7}+\dfrac{-4}{7}=\dfrac{-3}{7}\)
e) \(\dfrac{-1}{16}-\dfrac{1}{15}=\dfrac{-15}{240}-\dfrac{16}{240}=\dfrac{-31}{240}\)
Giải:
a) \(\dfrac{1}{7}+\dfrac{-4}{7}=\dfrac{1+\left(-4\right)}{7}=\dfrac{-3}{7}\)
e) \(\dfrac{-1}{16}-\dfrac{1}{15}=\dfrac{-15}{240}-\dfrac{16}{240}=\dfrac{-15-16}{240}=\dfrac{-31}{240}\)