Question

Giải các phương trình:

 

\(a,x^2+2x-15=0\)

\(b,9x^2-1=\left(3x+1\right)\left(4x+1\right)\)

\(c,2x^3+3x^2-32x=48\)

Answer 1

\(a,\Leftrightarrow\left(x+5\right)\left(x-3\right)=0\Leftrightarrow x\in\left\{-5;3\right\}\)

\(b,\Leftrightarrow\left(3x-1\right)\left(3x+1\right)=\left(3x+1\right)\left(4x+1\right)\)

\(\Leftrightarrow\orbr{\begin{cases}3x+1=0\\3x-1=4x+1\end{cases}}\)

\(c,\Leftrightarrow\left(2x^3-32x\right)+\left(3x^2-48\right)=0\Leftrightarrow2x\left(x-4\right)\left(x+4\right)+3\left(x-4\right)\left(x+4\right)\)

\(\Leftrightarrow\left(2x+3\right)\left(x+4\right)\left(x-4\right)=0\Leftrightarrow......\)

Answer 2

a, x1=3 ; x2=-5

b,x1=-2 ; x2=-1/3