Question

giá trị x thỏa mãn

\(\frac{|x|}{186}=\left(1-\frac{303030}{313131}\right)+\left(\frac{616161}{626262}-1\right)\)là x=

Answer 1

\(\pm3\)

Answer 2

\(\frac{|x|}{186}=\left(1-\frac{30}{31}\right)+\left(\frac{60}{61}-1\right)\)

\(\Leftrightarrow|x|=186\left(\frac{1}{31}-\frac{1}{61}\right)\)

\(\Leftrightarrow|x|=6-\frac{186}{61}\)

\(\Leftrightarrow|x|=\frac{180}{61}\)

\(\Leftrightarrow x=\pm\frac{180}{61}\)

Answer 3

\(\frac{|x|}{186}=\left(1-\frac{303030}{313131}\right)+\left(\frac{616161}{626262}-1\right)\)

\(\frac{|x|}{186}=\left(1-\frac{30}{31}\right)+\left(\frac{61}{62}-1\right)\)

\(\frac{|x|}{186}=1-\frac{30}{31}+\frac{61}{62}-1\)

\(\frac{|x|}{186}=\left(1-1\right)+\left(\frac{61}{62}-\frac{30}{31}\right)\)

\(\frac{|x|}{186}=\frac{1}{62}\)

\(\Rightarrow|x|=186.\frac{1}{62}\)

\(|x|=3\)

\(\Rightarrow x=\pm3\)