x/2 + x/4 + x/2016 = x/3 + x/5 + x/2017
=> x/2 + x/4 + x/2016 - x/3 - x/5 - x/2017 = 0
=> x.(1/2 + 1/4 + 1/2016 - 1/3 - 1/5 - 1/2017) = 0
Vì 1/2 > 1/3; 1/4 > 1/5; 1/2016 > 1/2017
=> 1/2 + 1/4 + 1/2016 - 1/3 - 1/5 - 1/2017 khác 0
=> x = 0
Ta có:
\(\frac{x}{2}+\frac{x}{4}+\frac{x}{2016}=\frac{x}{3}+\frac{x}{5}+\frac{x}{2017}\)
=>\(\frac{x}{2}+\frac{x}{4}+\frac{x}{2016}-\frac{x}{3}-\frac{x}{5}-\frac{x}{2017}=0\)
=>\(x.\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{2016}-\frac{1}{3}-\frac{1}{5}-\frac{1}{2017}\right)=0\)
áp dụng t/c : A.B=0 =>hoặc A=0 hoặc B=0 ta có:
Vì \(\frac{1}{2}+\frac{1}{4}+\frac{1}{2016}-\frac{1}{3}-\frac{1}{5}-\frac{1}{2017}\ne0\)
=>x=0
