|x-2|+2|x-y|=0
Vì |x-2| \(\ge\) 0 với mọi x
2|x-y| \(\ge\) 0 với mọi x;y
=>|x-2|+2|x-y| \(\ge\) 0 với mọi x;y
Dấu "=" xảy ra
<=>|x-2|=2|x-y|=0
+)|x-2|=0<=>x=2
+)2|x-y|=0<=>x-y=0<=>x=y<=>y=2
Vậy.....................
bai 1 so cac gia tri nguyen cua x de gia tri tuyet doi cua x + gia tri tuyet doi cua x-2 =0
bai 2 so cac gia tri nguyen cua x thoa man gia tri tuyet doi cua x-3 + gia tri tuyet doi cua 8-2x = 1 là
giá tri tuyet doi cua x+93 + gia tri tuyet doi cua-y+17=0
gia tri tuyet doi cua 7-x= gia tri tuyet doi cua x+3 tim x
tim so nguyen x, biet
a. 7 - x = 8 - ( -7 )
b. x - 8 = ( -3 ) = -8
tim so nguyen a, biet
a. gia tri tuyet doi a gia tri tuyet doi = 2
b. gia tri tuyet doi a + 2 gia tri tuyet doi = 0
gia tri tuyet doi cua x-1+gia tri tuyet doi x+3=4
tim x
gia tri tuyet doi cua -x+5=gia tri tuyet doi cua 1-5
gia tri tuyet doi x-42017+gia tri tuyet doi y=0
cho x ; y la cac so nguyen to sao cho gia tri tuyet doi cua x cong gia tri tuyet doi cua y bang 5 so cap so nguyen (x;y) thoa man la
gia tri tuyet doi cua x+1/2=0
