Question

Giá trị của biểu thức A = 3¹² + 5¹³ + 7^{15 +} 11²⁰¹⁰ chia cho 5 có số dư là bao nhiêu?

Answer 1

\(3^{12}+5^{13}+7^{15}+11^{2010}\)

\(=\left(3^4\right)^3+\left(...5\right)+\left(7^4\right)^3.7^3+\left(...1\right)\)

\(=\left(...1\right)^3+\left(...5\right)+\left(...1\right)^2.343+\left(...1\right)\)

\(=\left(...1\right)+\left(...5\right)+\left(...3\right)+\left(...1\right)\)

\(=\left(...0\right)\)chia 5 dư 0

Answer 2

dai dong qua ban oi

Answer 3

Sao khó thế

Answer 4

\(A=3^{12}+5^{13}+7^{15}+11^{2010}\)

\(A=\left(3^2\right)^6+\left(...5\right)+\left(7^2\right)^7.7+\left(...1\right)\)

\(A=9^6+\left(...5\right)+49^7.7+\left(...1\right)\)

\(A=\left(...1\right)+\left(...5\right)+\left(...9\right).7+\left(...1\right)\)

\(A=\left(...1\right)+\left(...5\right)+\left(...3\right)+\left(...1\right)\)

\(A=\left(...0\right)\)

Vậy A chia 5 dư 0

Answer 5

Xét c/s tận cùng là ngắn r