\(1,x=2\Leftrightarrow A=3\cdot4-4\cdot2+1=12-8+1=5\\ 2,B=x^3-1+x^2-x-2-x^3=x^2-x-3\\ 3,C=B-A=x^2-x-3-3x^2+4x-1\\ \Leftrightarrow C=-2x^2-3x-4=-2\left(x^2+2\cdot\dfrac{3}{4}x+\dfrac{9}{16}+\dfrac{23}{16}\right)\\ C=-2\left(x+\dfrac{3}{4}\right)^2+\dfrac{23}{8}\le\dfrac{23}{8}\\ C_{max}=\dfrac{23}{8}\Leftrightarrow x=-\dfrac{3}{4}\)
