\(\dfrac{7}{10}\times\left(3+5+2\right)=\dfrac{7}{10}\times10=7\)
\(3\times\dfrac{7}{10}\times\dfrac{7}{10}\times5+2\times\dfrac{7}{10}=\dfrac{7}{10}\times\left(3+5+2\right)=\dfrac{7}{10}\times10=7\)
\(\dfrac{7}{10}\times\left(2+5+3\right)=\dfrac{7}{10}\times10=\dfrac{7}{10}\times\dfrac{10}{1}=7\)
= 7/10 x (3 + 5 + 2)
=7/10 x 10
= 7 x 10/10
= 7x1/1
=7
Vậy giá trị biểu thức là 7
=(3+5+2)x\(\dfrac{7}{10}\)=10x\(\dfrac{7}{10}\)=7
\(=\left(3+5+2\right)\times\dfrac{7}{10}=10\times\dfrac{7}{10}=7\)
