\(\frac{x}{y}=\frac{3}{4}\)
\(\Rightarrow\frac{x}{3}=\frac{y}{4}\)
Đặt : \(\frac{x}{3}=\frac{y}{4}=k\)
\(\Rightarrow x=3k;y=4k\)
Khi đó ; \(3k.4k=192\)
\(\Rightarrow12k^2=192\)
\(\Rightarrow k^2=192:12=16\)
\(\Rightarrow k=4\)hoặc \(k=-4\)
\(\Rightarrow x=3.4=12;y=4.4=16\)hoặc
\(x=3.\left(-4\right)=-12;y=4.\left(-4\right)=-16\)
\(\frac{x}{y}=\frac{3}{4}\)
\(\Rightarrow\frac{x}{3}=\frac{y}{4}\)
đặt x/3 = y/4 = k
\(\Rightarrow\hept{\begin{cases}x=3k\\y=4k\end{cases}}\)
\(\Rightarrow xy=3k\cdot4k=12k^2\) mà xy = 192
\(\Rightarrow k^2=192\div12\)
\(\Rightarrow k^2=16\)
\(\Rightarrow k=\pm4\)
dễ r đó bn
Ta có: \(\frac{x}{y}=\frac{3}{4}\)
\(\Rightarrow\frac{x}{3}=\frac{y}{4}\)
Đặt \(\frac{x}{3}=\frac{y}{4}=k\)
\(\Rightarrow x=3k;y=4k\)
\(\Rightarrow xy=3k.4k=12k^2=192\)
\(\Rightarrow k^2=16\)
\(\Rightarrow\orbr{\begin{cases}k=4\\k=-4\end{cases}}\)
Với \(k=4\Rightarrow\hept{\begin{cases}x=3.4=12\\y=4.4=16\end{cases}}\)
Với \(k=-4\Rightarrow\hept{\begin{cases}x=3.\left(-4\right)=-12\\y=4.\left(-4\right)=-16\end{cases}}\)
Vậy \(\orbr{\begin{cases}x=12;y=16\\x=-12;y=-16\end{cases}}\)
Tham khảo nhé~
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Ta có
\(\frac{x}{y}=\frac{3}{4}\Rightarrow\frac{x}{3}=\frac{y}{4}\)
Với x,y cùng dấu ta có
\(\frac{x^2}{9}=\frac{y^2}{16}=\frac{xy}{12}=\frac{192}{12}=16\)(vì xy=192)
\(\Rightarrow x^2=16\cdot9=144\Rightarrow x=\pm12\)
\(y^2=16\cdot16=256\Rightarrow y=\pm16\)
