Question

\(\frac{x+6}{15}=\frac{5-x}{7}\)

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Answer 1

\(\frac{x+6}{15}=\frac{5-x}{7}\)

\(\Leftrightarrow\left(x+6\right).7=\left(5-x\right).15\)

\(\Leftrightarrow7x+42=75-15x\)

\(\Leftrightarrow7x+15x=75-42\)

\(\Leftrightarrow22x=33\)

\(\Leftrightarrow x=\frac{3}{2}\)

Answer 2

=> 7.(x+6)= 15.(5-x)

=> 7x +7.6=15.5-15x

=> 7x + 42= 75 -15x

=> 7x+15x=75-42

=> 22x=33

=>x= 1,5

Answer 3

\(\frac{x+6}{15}=\frac{5-x}{7}\)

\(\Rightarrow\frac{x+6}{15}-\frac{5-x}{7}=0\)

\(\Rightarrow\frac{7.\left(x+6\right)}{7.15}+\frac{15.\left(x-5\right)}{7.15}=0\)

\(\Rightarrow\frac{7x+42}{105}+\frac{15x-75}{105}=0\)

\(\Rightarrow\frac{7x+42+15x-75}{105}=0\)

\(\Rightarrow\frac{22x-33}{105}=0\)

\(\Rightarrow22x+33=0\Rightarrow22x=33\)

\(\Rightarrow x=\frac{33}{22}=\frac{3}{2}\)

Answer 4

\(\frac{x+6}{15}=\frac{5-x}{7}\)

\(\Leftrightarrow7x+42=75-15x\)

\(\Leftrightarrow7x=75-15x-42\)

\(\Leftrightarrow7x=-15x+33\)

\(\Leftrightarrow7x+15x=33\)

\(\Leftrightarrow\frac{22x}{22}=\frac{33}{22}\)

\(\Rightarrow x=\frac{3}{2}=1,5\)

Answer 5

Từ \(\frac{x+6}{15}=\frac{5-x}{7}\)

\(\Rightarrow7\left(x+6\right)=15\left(5-x\right)\)

\(\Rightarrow7x+42=75-15x\)

\(\Rightarrow7x+15x=75-42\)

\(\Rightarrow22x=33\)\(\Rightarrow x=\frac{33}{22}=\frac{3}{2}\)

Vậy \(x=\frac{3}{2}\)