\(\Rightarrow x^2=16.4\)
\(\Rightarrow x^2=64\)
x=-8 hoặc 8
\(\frac{x}{4}=\frac{16}{x}\)
\(\Rightarrow x^2=16.4\)
\(\Rightarrow x^2=64\)
\(\Rightarrow x=8\)hoặc \(-8\)
\(\)
\(\frac{x}{4}=\frac{16}{x}\)
=>x2=16.4
=>x2=64
=>x2=82=(-8)2
=>x E{8;-8}
\(\Rightarrow x^2=16.4\)
\(\Rightarrow x^2=64\)
x=-8 hoặc 8
\(\frac{x}{4}=\frac{16}{x}\)
\(\Rightarrow x^2=16.4\)
\(\Rightarrow x^2=64\)
\(\Rightarrow x=8\)hoặc \(-8\)
\(\)
\(\frac{x}{4}=\frac{16}{x}\)
=>x2=16.4
=>x2=64
=>x2=82=(-8)2
=>x E{8;-8}
\(\frac{1}{1-x}+\frac{1}{1+x}+\frac{2}{1+x^2}+\frac{4}{1+x^4}+\frac{8}{1+x^8}+\frac{16}{1+x^{16}}\)
Chứng minh \(F=\frac{3}{2}\cdot x^4-\frac{1}{16}\cdot x^4+\frac{1}{32}\cdot x^4-\frac{1}{4}\cdot x^4>0\)với mọi x khác 0
Tìm x biết
\(\frac{x+4}{9}+\frac{x+11}{8}+\frac{x+16}{7}=10-\frac{x+19}{6}\)
\(\frac{x-2}{3}=\frac{4}{5}\)
\(\frac{x+3}{-4}=\frac{5}{20}\)
\(\frac{3}{x-1}=\frac{21}{16}\)
a,\(\frac{X}{Y+Z+1}=\frac{Y}{X+Z+3}=\frac{Z}{Y+X-4}=X+Y+Z\)+Z
b,\(\frac{x-18}{x+4}=\frac{x-17}{x+16}\)tìm x
\(\frac{X}{-4}=\frac{-16}{x}\)
D , \ 10\ x \ \sqrt{0.04}\ \ \sqrt{\frac{4}{25}}\ \ \frac{1}{16}\ x \ \sqrt{64}\ \ \frac{1}{4}\ x \ \sqrt{4}\
Ai Nhanh Mk Tick Đúng Trc Nhé
tìm x ( giải rõ ràng ko bấm máy)
\(\frac{x+1}{5}=\frac{-10}{16}\)
\(x+\frac{4}{5.9}+\frac{4}{9.13}+\frac{4}{13.17}+......+\frac{4}{41.45}=\frac{-37}{45}\)
\(\left(\frac{1}{3}x-\frac{1}{4}\right)^2+\left(x^2-\frac{9}{16}\right)^4=0\)