Question

\(\frac{x+3}{x-2}+\frac{x+2}{x}=2\)

mk cần gấp mong các bạn giúp đỡ

 

 

Answer 1

Đkxđ: \(\hept{\begin{cases}x\ne2\\x\ne0\end{cases}}\)

\(\frac{x+3}{x-2}+\frac{x+2}{x}=2\) 

\(\Leftrightarrow\frac{x\left(x+3\right)}{x\left(x-2\right)}+\frac{\left(x-2\right)\left(x+2\right)}{\left(x-2\right)x}=\frac{2x\left(x-2\right)}{x\left(x-2\right)}\)

\(\Rightarrow x\left(x+3\right)+\left(x-2\right)\left(x+2\right)=2x\left(x-2\right)\)

\(\Leftrightarrow x^2+3x+x^2-4=2x^2-4x\)

\(\Leftrightarrow x^2+3x+x^2-2x^2+4x=4\)

\(\Leftrightarrow7x=4\)

\(\Leftrightarrow x=\frac{4}{7}\)