\(\frac{x}{2}=\frac{y}{3};\frac{y}{4}=\frac{z}{5}\Rightarrow\frac{x}{8}=\frac{y}{12}=\frac{z}{15}\)
Theo t/s dãy tỉ số bằng nhau có:
\(\frac{x}{8}=\frac{y}{12}=\frac{z}{15}=\frac{x+y-z}{8+12-15}=\frac{10}{5}=2\)
=>\(\frac{x}{8}=2\Rightarrow x=2.8=16\)
=>\(\frac{y}{12}=2\Rightarrow y=2.12=24\)
=>\(\frac{z}{15}=2\Rightarrow z=2.15=30\)
Vậy x=16; y=24; z=30.
\(\frac{x}{2}=\frac{y}{3};\frac{y}{4}=\frac{z}{5}\)
=> \(\frac{x}{8}=\frac{y}{12};\frac{y}{12}=\frac{z}{15}\)
=> \(\frac{x}{8}=\frac{y}{12}=\frac{z}{15}=\frac{x+y-z}{8+12-15}=\frac{10}{5}=2\)
=> x=2.8=16
y=2.12=24
z=2.15=30