(x+2)/11+(x+2)/12+(x+2)/13=(x+2)/14+(x+2)/15
(x+2)(1/11+1/12+1/13)=(x+2)(1/14+1/15)
(x+2)(1/11+1/12+1/13)-(x+2)(1/14+1/15)=0
(x+2)(1/11+1/12+1/13-1/14-1/15)=0
mà 1/11+1/12+1/13-1/14-1/15 #0
nên x+2=0
x=0-2
x=-2
Vậy x=-2
tìm x
\(\frac{x+2}{11}+\frac{x+2}{12}+\frac{x+2}{13}=\frac{x+2}{14}+\frac{x+2}{15}\)
Tìm x:
\(\frac{x-2}{11}+\frac{x-2}{12}+\frac{x-2}{13}=\frac{x-2}{14}+\frac{x-2}{15}\)
tìm x
\(A=\frac{x+2}{10}+\frac{x+2}{11}+\frac{x+2}{12}+\frac{x+2}{13}=\frac{x+2}{14}+\frac{x+2}{15}\)
\(\frac{x+2}{11}+\frac{x+2}{12}+\frac{x+2}{13}=\frac{x+2}{14}+\frac{x+2}{15}\)
Giá trị x thỏa mãn \(\frac{x+2}{11}+\frac{x+1}{12}+\frac{x+13}{13}=\frac{x-1}{14}+\frac{x-2}{15}\)
Bạn nào giúp mình với!
tìm x,biết:
a)\(\frac{2}{\left(x+2\right)\left(x+4\right)}+\frac{4}{\left(x+4\right)\left(x+8\right)}+\frac{6}{\left(x+8\right)\left(x+14\right)}=\frac{x}{\left(x+2\right)\left(x+14\right)}\)
b)\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
c)\(\left(x+2\right)^2=\frac{38}{25}+\frac{9}{10}-\frac{11}{15}+\frac{13}{21}-\frac{15}{28}+\frac{17}{36}-...+\frac{197}{4851}-\frac{199}{4950}\)
giúp tớ với,huhu
Tìm x biết:\(\frac{x+2}{11}+\frac{x+2}{12}+\frac{x+2}{13}=\frac{x+2}{14}+\frac{x+2}{15}\)
Nhanh nhanh,ns cách làm thôi cũng đc nha!!!!!!!!!!!
Tìm x biết:
\(\frac{x+2}{11}+\frac{x+2}{12}+\frac{x+2}{13}=\frac{x+2}{14}+\frac{x+2}{15}\)
Bài này dễ mà phải không các bạn
TÌM X ,BIẾT:
a) \(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}+\frac{x+249}{5}=0\)
b)\(\frac{x+2}{11}+\frac{x+2}{12}+\frac{x+2}{13}=\frac{x+2}{14}+\frac{x+2}{15}\)
