Question

\(\frac{x+2005}{2004}\)-\(\frac{x+2005}{2001}\)= \(\frac{x+2005}{2002}\)-\(\frac{x+2005}{2003}\)

Answer 1

\(\frac{x+2005}{2004}-\frac{x+2005}{2001}=\frac{x+2005}{2002}-\frac{x+2005}{2003}\)

\(\frac{x+2005}{2004}-\frac{x+2005}{2001}+\frac{x+2005}{2003}-\frac{x+2005}{2002}=0\)

\(\left(x+2005\right).\left(\frac{1}{2004}-\frac{1}{2001}+\frac{1}{2003}-\frac{1}{2002}\right)=0\)

=> x + 2015 = 0

=> x = -2015

Vậy x = -2015

Answer 2

TL :

\(\frac{x+2005}{2004}-\frac{x+2005}{2001}=\frac{x+2005}{2002}-\frac{x+2005}{2003}\)

\(\frac{x+2005}{2004}-\frac{x+2005}{2001}+\frac{x+2005}{2002}-\frac{x+2005}{2003}=0\)

Ta có : \(\left(x+2005\right).\left(\frac{1}{2004}-\frac{1}{2001}+\frac{1}{2003}-\frac{1}{2002}\right)=0\)

\(\Rightarrow x+2005=0\)

\(\Rightarrow x=-2005\)

Answer 3

Chuyển vế rồi tách x+2005 ra nhé