\(\frac{x+2}{-18}=\frac{-8}{x+2}=\frac{-18}{-8}=10\)
Vậy x = 10
\(\frac{x+2}{-18}=\frac{-8}{x+2}\)
\(\Rightarrow\left(x+2\right)\left(x+2\right)=-18.\left(-8\right)\)
\(\Leftrightarrow\left(x+2\right)^2=144\)
\(\Leftrightarrow\left(x+2\right)=12\) hoặc \(\left(x+2\right)=-12\)
\(\Leftrightarrow x=10\) hoặc \(x=-14\)