Question

\(\frac{x+1}{x-4}=\frac{x+5}{x-7}\)

Giúp mình nhé. Help me😭😭

Answer 1

\(\Leftrightarrow\)\(\frac{\left(x+1\right)\left(x-7\right)}{\left(x-4\right)\left(x-7\right)}=\frac{\left(x+5\right)\left(x-4\right)}{\left(x-4\right)\left(x-7\right)}\)

\(\Rightarrow\)\(^{x^2-7x+x-7=x^2-4x+5x-20}\)

\(\Leftrightarrow\)\(x^2-x^2-6x-x-7+20=0\)

\(\Leftrightarrow-7x+13=0\)

\(\Leftrightarrow-7x=-13\)

\(\Rightarrow x=\frac{13}{7}\)

Answer 2

\(pt\Leftrightarrow\left(x+1\right)\left(x-7\right)=\left(x-4\right)\left(x+5\right)\)

\(\Leftrightarrow x^2-7x+x-7=x^2+5x-4x-20\)

\(\Leftrightarrow-7x=-13\Rightarrow x=\frac{13}{7}\)

Answer 3

dua lon ay