ta có \(x+1.x+1=8.2=16\)
\(x+1.x+1=4^2\)
\(x+1=4\)
\(x=3\)
Theo đầu bài ta có:
\(\frac{x+1}{2}=\frac{8}{x+1}\)
\(\Rightarrow\left(x+1\right)\left(x+1\right)=2\cdot8\)
\(\Rightarrow\left(x+1\right)^2=16\)
\(\Rightarrow x+1=\sqrt{16}\)
\(\Rightarrow x=4-1\)
\(\Rightarrow x=3\)
\(\frac{x+1}{2}\)=\(\frac{8}{x+1}\)Từ đây suy ra : x = 8:2=4 ; Thử đúng