Ta có; vậy
=> (x+1)2 = 2 x 8
=> (x + 1)2 = 16
=> x + 1 = 4
=> x = 3
Bài này mình biết :
\(\frac{x+1}{2}=\frac{8}{x+1}\)
\(=\left(x+1\right)^2=8\times2\)
\(=\left(x+1\right)^2=16\)
\(=\left(x+1\right)=\sqrt{16}\)
\(=\left(x+1\right)=4\)
\(=x=4-1\)
\(=x=3\)
\(\frac{x+1}{2}=\frac{8}{x+1}\Leftrightarrow\left(x+1\right)^2=16=4^2\)
\(\Rightarrow x+1=4\)hoặc \(x+1=-4\)
\(\Rightarrow x=3\) hoặc \(x=-5\)
\(\frac{x+1}{2}=\frac{8}{x+1}\)
= \(\left(x+1\right)^2=8x2\)
= \(\left(x+1\right)^2=16\)
= \(x+1=\sqrt{16}\)
= \(x+1=4\)
= \(x=4-1\)
= \(x=3\)
