\(\frac{x+1}{2016}-\frac{x+2}{2015}=\frac{x+2017}{2014}\)
\(\frac{x+1+2016}{2016}-\frac{x+2+2015}{2015}-\frac{x+2017}{2014}=0\)
\(\frac{x+2017}{2016}-\frac{x+2017}{2015}-\frac{x+2017}{2014}=0\)
\(\left(x+2017\right)\left(\frac{1}{2016}-\frac{1}{2015}-\frac{1}{2014}\right)=0\)
Vì \(\left(\frac{1}{2016}-\frac{1}{2015}-\frac{1}{2014}\right)\ne0\)
\(\Rightarrow x+2017=0\)
\(\Rightarrow x=-2017\)
Tìm x :
\(\frac{x=2015}{2016}+\frac{x+2016}{2015}+\frac{x+2017}{2014}=-3\)
Tìm x,biết:
\(\frac{x+4}{2014}+\frac{x+3}{2015}=\frac{x+2}{2016}+\frac{x+1}{2017}\)
Tìm x biết:
\(\frac{x-1}{2017}+\frac{x-2}{2016}-\frac{x-3}{2015}=\frac{x-4}{2014}\)
\(\frac{x+1}{2013}+\frac{x+1}{2014}+\frac{x+1}{2015}=\frac{x+1}{2016}+\frac{x+1}{2017}\)
t đg cần gấp
tìm x, y, z biết rằng: \(\frac{x^2}{2014}+\frac{y^2}{2015}+\frac{z^2}{2016}=\frac{x^2+y^2+z^2}{2017}\)
\(^{\frac{x^2}{2014}+\frac{y^2}{2015}+\frac{z^2}{2016}=\frac{x^2+y^2+z^2}{2017}}\)
tìm x, y, z
a)|3x-5|=(-2)2 \(b.\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)
\(c.\frac{x+4}{2014}+\frac{x+3}{2015}=\frac{x+2}{2016}+\frac{x+1}{2017}\)
So sánh M và N biết:
M=\(\frac{2014}{2015}+\frac{2015}{2016}+\frac{2016}{2017}\)
N=\(\frac{2014+2015+2016}{2015+2016+2017}\)
Tim x
\(\frac{x+2015}{5}+\frac{x+2016}{4}=\frac{x+2017}{3}+\frac{x+2018}{2}\)
2/ tim x
\(\frac{x+2015}{5}+\frac{x+2016}{6}=\frac{x+2017}{7} +\frac{x+2018}{8}\)
3/ tim x
\(\frac{1}{3}+\frac{1}{6}+\frac{99}{101}+\frac{1}{15}+... +\frac{1}{x\left(2x+1\right)}=\frac{1}{10}\)
