(x+100)*(1/99+1/96+1/93+1/91)=0
suy ra x+100=0
suy ra x=-100
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Giải phương trình sau
\(\frac{x+1}{99}+\frac{x+2}{98}=\frac{x+3}{97}+\frac{x+4}{96}\)
\(\frac{109-x}{91}+\frac{107-x}{93}+\frac{105-x}{95}+\frac{103-x}{97}+4=0\)
Giải phương trình sau
a,\(2\left(\frac{11x}{12}+\frac{1}{3}\right)=2-\frac{x}{6}\)
b,\(\frac{x+1}{99}+\frac{x+2}{98}=\frac{x+3}{97}+\frac{x+4}{96}\)
c,\(\frac{109-x}{91}+\frac{107-x}{93}+\frac{105-x}{95}+\frac{103-x}{97}+4=0\)
Tìm x, biết
\(\frac{1}{x\left(x+1\right)}\)+ \(\frac{1}{\left(x+1\right)\left(x+2\right)}\)+ ... + \(\frac{1}{\left(x+99\right)\left(x+100\right)}\)= \(\frac{100}{101}\)
\(\frac{x-5}{100}+\frac{x-4}{101}+\frac{x-3}{102}=\frac{x-100}{5}+\frac{x-101}{4}+\frac{x-102}{3}\)
Tìm x, biết:
\(\frac{1}{x\left(x+1\right)}\)+ \(\frac{1}{\left(x+1\right)\left(x+2\right)}\)+ ... + \(\frac{1}{\left(x+99\right)\left(x+100\right)}\)= \(\frac{100}{101}\)
1/ Cho \(\frac{x}{a}+\frac{y}{b}+\frac{z}{c}=1\) và \(\frac{a}{x}+\frac{b}{y}+\frac{c}{z}=0\). Chứng minh \(\frac{x^2}{a^2}+\frac{y^2}{b^2}+\frac{z^2}{c^2}=1\)
2/ Tính nhanh \(\left(100^2+98^2+96^2+...+2^2\right)-\left(99^2+97^2+95^2+...+1^2\right)\)
Giải phương trình
a,\(\frac{x-5}{100}+\frac{x-4}{101}+\frac{x-3}{102}=\frac{x-100}{5}+\frac{x-101}{4}+\frac{x-102}{3}\)
b, \(\frac{29-x}{21}+\frac{27-x}{23}+\frac{25-x}{25}+\frac{23-x}{27}+\frac{21-x}{29}=-5\)
\(\frac{x-5}{100}+\frac{x-4}{101}+\frac{x-3}{102}\) = \(\frac{x-100}{5}+\frac{x-101}{4}+\frac{x-102}{3}\) giai phuong trinh do ae giup mik vs nhe
\(\frac{1927-x}{91}+\frac{1925-x}{93}+\frac{1923-x}{95}+\frac{1921-x}{97}+4=0\)=0