\(\frac{x-1}{2005}=\frac{3-y}{2006}=\frac{\left(x-1\right)+\left(3-y\right)}{2005+2006}=\frac{x-y+2}{4011}=\frac{4009+2}{4011}=1\)
\(\Leftrightarrow x-1=2005\Leftrightarrow x=2006\)
\(\Leftrightarrow3-y=2006\Leftrightarrow y=3-2006=-2003\)
\(\frac{x-1}{2005}=\frac{3-y}{2006}\)và x-y = 4009
\(\frac{x-1}{2005}=\frac{3-y}{2006}vax-y=4009\)
\(\frac{x-1}{2005}=\frac{3-y}{2006}\) và x - y = 4009
\(\frac{x-1}{2005}=\frac{3-y}{2006}\)và x-y=4009
tìm x;y biết:
\(\frac{x-1}{2005}=\frac{3-y}{2006}\) và x-y=4009
\(\frac{x-1}{2005}=\frac{3-y}{2006}\) và x-y = 4009
Tìm x,y,z:
\(\frac{x-1}{2005}=\frac{3-y}{2006};x-y=4009\)
thks
\(\frac{x-1}{2005}=\frac{3-y}{2006}\) và x-y=4009
tìm x,y,z
\(\frac{x-1}{2005}=\frac{3-y}{2006}\)và x-y=4009
