\(\frac{x-1}{2005}=\frac{3-y}{2006}=\frac{x-1+3-y}{2005+2006}=\frac{x-y-1+3}{4011}=\frac{4009-1+3}{4001}=\frac{4011}{4011}=1\)
=>x-1/2005=1=>x-1=2005=>x=2006
=>3-y/2006=1=>3-y=2006=>y=-2003
\(\frac{x-1}{2005}=\frac{3-y}{2006}\)và x-y = 4009
\(\frac{x-1}{2005}=\frac{3-y}{2006}\) và x - y = 4009
\(\frac{x-1}{2005}=\frac{3-y}{2006}\)và x-y=4009
tìm x;y biết:
\(\frac{x-1}{2005}=\frac{3-y}{2006}\) và x-y=4009
\(\frac{x-1}{2005}=\frac{3-y}{2006}\) và x-y=4009
tìm x,y,z
\(\frac{x-1}{2005}=\frac{3-y}{2006}\)và x-y=4009
a)\(\frac{x-1}{2005}=\frac{3-y}{2006}\)và x-y=4009
b)\(\frac{x}{2}=\frac{y}{3};\frac{y}{4}=\frac{z}{5}\)và x-y-z=28
Cho \(\frac{x-1}{2005}=\frac{3-y}{2006}\) và x-y= 4009. Tìm x, y
\(\frac{x-1}{2005}=\frac{3-y}{2006}vax-y=4009\)
