\(\frac{\sqrt{3-\sqrt{5}}\left(3+\sqrt{5}\right)}{\sqrt{10}+\sqrt{2}}=\frac{\sqrt{\left(3-\sqrt{5}\right)\left(3+\sqrt{5}\right)}.\sqrt{3+\sqrt{5}}}{\sqrt{\left(\sqrt{10}+\sqrt{2}\right)^2}}\)\(=\frac{2\sqrt{3+\sqrt{5}}}{\sqrt{12+4\sqrt{5}}}=\frac{\sqrt{12+4\sqrt{5}}}{\sqrt{12+4\sqrt{5}}}=1\)