Question

\(\frac{\left|x\right|}{186}=\left(1-\frac{303030}{313131}\right)+\left(\frac{616161}{626262}-1\right)+\left(\frac{929292}{939393}-1\right)\)

tìm x

Answer 1

\(1-\frac{303030}{313131}+\frac{616161}{626262}-1+\frac{929292}{939393}-1=\left(1-\frac{30}{31}\right)+\left(\frac{61}{62}-1\right)+\left(\frac{92}{93}-1\right)\)

\(=\frac{1}{31}-\frac{1}{62}-\frac{1}{93}=\frac{1}{186}\)

=> \(\frac{\left|x\right|}{186}=\frac{1}{186}\)=> |x| = 1 => x = 1 hoặc x = - 1

Vậy...............

Answer 2

303030/313131=30/31(1)

616161/626262=61/62(2)

929292/939393=92/92(3)

từ 1,2,3=>tự làm

Answer 3

phải làm mới đc **** chứ !