Question

\(\frac{\left(x-2\right)^2}{3}-\frac{2x+1}{4}=4-\frac{\left(2x-3\right)^2}{6}\)

Giai phuong trinh

Answer 1

-------------------ko chép đề nha---------

\(\Leftrightarrow\frac{4\left(x^2-4x+4\right)-3\left(2x+1\right)}{12}=\frac{12-2\left(4x^2-12x+9\right)}{12}\)

\(\Rightarrow4x^2+16x+16-6x-3=12-8x^2+24x-18\)

\(\Leftrightarrow4x^2+10x+13=-8x^2+24x-6\)

\(\Leftrightarrow4x^2+8x^2+10x-24x+13+6=0\)

\(\Leftrightarrow12x-14x+19=0\)

Ta có :\(\Delta'=7^2-12.19=-179< 0\)

\(\Rightarrow\)phương trình vô nghiệm