Question

\(\frac{\left(\frac{-1}{9}\right)^0.3^2.9^3}{729}\)

Answer 1

Trả lời

(-1/9)⁰.3².9³/729

=1.3².9³/9³

=3²=9

Answer 2

\(\frac{\left(-\frac{1}{9}\right)^0.3^2.3^3}{729}=\frac{1.3^5}{3^6}=\frac{1}{3}\)

Answer 3

\(\frac{\left(-\frac{1}{9}\right)^0\cdot3^2\cdot9^3}{729}\)

\(=\frac{1\cdot3^2\cdot9^3}{3^6}\)\(=\frac{1\cdot3^2\cdot3^6}{3^6}=1\cdot3^2=1\cdot9=9\)

Answer 4

Mk nhầm!

\(\frac{\left(-\frac{1}{9}\right)^0.3^2.9^3}{729}=\frac{3^2.3^6}{3^6}=3^2=9\)

Answer 5

\(\frac{\left(\frac{-1}{9}\right)^0\cdot3^2\cdot9^3}{729}\)
\(=\frac{3^2\cdot9^3}{9^3}\)

\(=3^2\)

\(=9\)

Answer 6

\(\frac{\left(-\frac{1}{9}\right)^0\cdot3^2\cdot9^3}{729}\)

\(=\frac{1\cdot3^2\cdot9^3}{9^3}\)

\(=3^2\)

\(=9\)

Answer 7

\(\frac{\left(-\frac{1}{9}\right)^0\cdot3^2\cdot9^3}{729}\)

\(=\frac{1\cdot3^2\cdot9^3}{9^3}\)

\(=3^2\)

\(=9\)