Question

\(\frac{\left(3X-1\right)\left(X+2\right)}{3}-\frac{2X^2+1}{2}=\frac{11}{2}\)

Answer 1

áp dụng tl thức ta có :

\(\Leftrightarrow\frac{10x-7}{6}=\frac{11}{2}\Rightarrow\left(10x-7\right)2=6.11\)

\(\Rightarrow\frac{\left(10x-7\right)2}{2}=\frac{6.11}{2}\)( chia 2 vế cho 2)

=>\(10x-7=\frac{6.11}{2}\)

=>10x-7=\(\frac{66}{2}\)

=>10x-7=33

=>10x=33+7

=>10x=40

=>x=40:10

=>x=4

Answer 2

<=> 2(3x-1)(x+2) - 3(2x²+1) = 33

<=> 6x²+12x-2x-4 - 6x²-3 = 33

<=> 10x=40

<=> x=4