\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^{19}}\)
\(\Leftrightarrow\)\(\frac{3^2.\left(2^2\right)^2.2^{16.2}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^{19}}\)
\(\Leftrightarrow\)\(\frac{2^4.2^{32}.3^2}{11.2^{35}-2^{76}}\)
\(\Leftrightarrow\)\(\frac{2^{36}.3^2}{2^{35}.\left(11-2^{41}\right)}\)
\(\Leftrightarrow\)\(\frac{2.3^2}{11-2^{41}}\)
Hết biết giải rồi
\(\frac{3^2.4^2.2^{32}}{11.2^{13}.2^{22}-2^{36}}=\frac{3^2.2^4.2^{32}}{11.2^{35}-2^{36}}\)\(=\frac{3^2.2^{36}}{2^{35}.\left(11-2\right)}=\frac{3^2.2}{9}=\frac{3^2.2}{3^2}=2\)
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\)\(\frac{3^2.2^{2.2}.2^{16.2}}{11.2^{13}.2^{11.2}-2^{4.9}}\)
\(=\)\(\frac{2^{36}.3^2}{11.2^{35}-2^{36}}\)
\(=\)\(\frac{2^{36}.3^2}{2^{35}.\left(11-2\right)}\)
\(=\)\(\frac{2.3^2}{9}\)
\(=\)\(\frac{2.3^2}{3^2}\)
\(=\)\(2\)
