\(\frac{\frac{4}{17}-\frac{4}{45}+\frac{4}{156}}{\frac{3}{17}-\frac{3}{45}+\frac{3}{156}}=\frac{4.\left(\frac{1}{17}-\frac{1}{45}+\frac{1}{156}\right)}{3.\left(\frac{1}{17}-\frac{1}{45}+\frac{1}{156}\right)}=\frac{4}{3}\)
\(\frac{\frac{4}{17}-\frac{4}{45}+\frac{1}{39}}{\frac{3}{17}-\frac{1}{15}+\frac{1}{52}}\)
\(=\frac{\frac{4}{17}-\frac{4}{45}+\frac{4}{156}}{\frac{3}{17}-\frac{3}{45}+\frac{3}{156}}\)
\(=\frac{\frac{1}{17}.4-\frac{1}{45}.4+\frac{1}{156}.4}{\frac{1}{17}.3-\frac{1}{45}.3+\frac{1}{156}.3}\)
\(=\frac{4\left(\frac{1}{17}-\frac{1}{45}+\frac{1}{156}\right)}{3\left(\frac{1}{17}-\frac{1}{45}+\frac{1}{156}\right)}\)
\(=\frac{4}{3}\)
