Question

   \(\frac{\frac{2}{5}-\frac{2}{9}+\frac{2}{11}}{\frac{7}{5}-\frac{7}{9}+\frac{7}{11}}:\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{7}{6}-\frac{7}{8}+\frac{7}{10}}=?\)

Answer 1

1 nha bn

Answer 2

bằng 1 nha bạn

 k tui nha

thanks

Answer 3

P/s : Đúng nha 

Ta có : 

\(\frac{\frac{2}{5}-\frac{2}{9}+\frac{2}{11}}{\frac{7}{5}-\frac{7}{9}+\frac{7}{11}}:\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{7}{6}-\frac{7}{8}+\frac{7}{10}}\)

\(=\frac{2\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}{7\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}:\frac{2\left(\frac{1}{6}-\frac{1}{8}+\frac{1}{10}\right)}{7\left(\frac{1}{6}-\frac{1}{8}+\frac{1}{10}\right)}\)

\(=\frac{2}{7}:\frac{2}{7}\)

\(=1\)

~ Ủng hộ nhé 

Answer 4

\(\frac{\frac{2}{5}-\frac{2}{9}+\frac{2}{11}}{\frac{7}{5}-\frac{7}{9}+\frac{7}{11}}:\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{7}{6}-\frac{7}{8}+\frac{7}{10}}=\frac{2\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}{7\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}:\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{7}{6}-\frac{7}{8}+\frac{7}{10}}\)

\(=\frac{2}{7}:\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{7}{6}-\frac{7}{8}+\frac{7}{10}}=\frac{2}{7}.\frac{7\left(\frac{1}{6}-\frac{1}{8}+\frac{1}{10}\right)}{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}\)

\(=\frac{2\left(\frac{1}{6}-\frac{1}{8}+\frac{1}{10}\right)}{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}=\frac{\frac{2}{6}-\frac{2}{8}+\frac{2}{10}}{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}=\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}=1\)

Answer 5

Bài này cs trong đề thi hsg năm ngoái thi nè :>

\(\frac{\frac{2}{5}-\frac{2}{9}+\frac{2}{11}}{\frac{7}{5}-\frac{7}{9}+\frac{7}{11}}:\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{7}{6}-\frac{7}{8}+\frac{7}{10}}=\frac{2\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}{7\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{11}\right)}:\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{7\left(\frac{1}{6}-\frac{1}{8}+\frac{1}{10}\right)}\)

\(=\frac{2}{7}:\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{7\left(\frac{1}{6}-\frac{1}{8}+\frac{1}{10}\right)}=\frac{2}{7}.\frac{7\left(\frac{1}{6}-\frac{1}{8}+\frac{1}{10}\right)}{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}\)

\(=2.\frac{\frac{1}{6}-\frac{1}{8}+\frac{1}{10}}{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}=\frac{\frac{2}{6}-\frac{2}{8}+\frac{2}{10}}{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}=\frac{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}{\frac{1}{3}-\frac{1}{4}+\frac{1}{5}}=1\)

Answer 6

bằng 1 nha bn eii