Các câu hỏi tương tự
\(Cho\frac{ab}{b}=\frac{bc}{a}=\frac{ca}{c}.CMR:\left(abc\right)^{123}\cdot a^{40}\cdot b^{41}\cdot c^{42}\)
Bài 1: Cho biết \(\frac{\overline{ab}}{b}=\frac{\overline{bc}}{c}=\frac{\overline{ca}}{a}\)
CM: (abc)123 = 111123 . a40 . b41 . c42
a) C/m: \(a^2+b^2+c^2=ab+bc+ca\Leftrightarrow a=b=c\)
b) C/m: \(T=x\left(x-a\right)\left(x+a\right)\left(x+2a\right)+a^4\ge0\) \(\forall x,a\in R\)
c) Tìm x sao cho: \(\frac{x+5}{2015}+\frac{x+4}{2016}+\frac{x+3}{2017}+\frac{x+2}{2018}=\frac{x+2015}{5}+\frac{x+2016}{4}+\frac{x+2017}{3}+\frac{x+2018}{2}\)
Chứng minh rằng nếu:
\(\frac{abc\left(b-c+a\right)-\left(ab\right)^2}{7776}=\frac{abc\left(c-a+b\right)-\left(bc\right)^2}{-19440}=\frac{abc\left(b-c+a\right)-\left(ca\right)^2}{-12960}\)
thì
\(4a=6b=9c\)
Cho dãy tỉ số \(\frac{\overline{ab}+\overline{bc}}{a+b}=\frac{\overline{bc}+\overline{ca}}{b+c}=\frac{\overline{ca}+\overline{ab}}{c+a}\)( với a,b,c\(\ne\)0 ) .Tính \(P=\left(1+\frac{a}{b}\right)\left(1+\frac{b}{c}\right)\left(1+\frac{c}{a}\right)\)
Cho a,b,c khác 0 thỏa mãn \(\frac{ab}{a+b}\)=\(\frac{bc}{b+c}\)=\(\frac{ca}{c+a}\)
Tính M = \(\frac{\left(ab+bc+ca\right)^{1007}}{a^{2014}+b^{2014}+c^{2014}}\)
1.Cho ab/b bc/cca/a. Tính A (a-b)(b-c)(c-a) + 20162. Cho (ab + bc)/ ( a+b) ( bc + ca )/(b+c) ( ca + ab) / (c+a)Tính Mleft(frac{b}{a}+1right)left(frac{c}{b}+1right)left(frac{a}{c}+1right)+20163. Cho a+b+c+d khác 0 và frac{a}{b+c+d}frac{b}{a+c+d}frac{c}{a+b+d}frac{d}{a+b+c}Tìm giá trị của Afrac{a+b}{c+d}+frac{b+c}{a+d}+frac{c+d}{a+b}+frac{d+a}{b+c}
Đọc tiếp
1.Cho ab/b = bc/c=ca/a. Tính A= (a-b)(b-c)(c-a) + 2016
2. Cho (ab + bc)/ ( a+b) = ( bc + ca )/(b+c)= ( ca + ab) / (c+a)
Tính M=\(\left(\frac{b}{a}+1\right)\left(\frac{c}{b}+1\right)\left(\frac{a}{c}+1\right)+2016\)
3. Cho a+b+c+d khác 0 và \(\frac{a}{b+c+d}=\frac{b}{a+c+d}=\frac{c}{a+b+d}=\frac{d}{a+b+c}\)
Tìm giá trị của A=\(\frac{a+b}{c+d}+\frac{b+c}{a+d}+\frac{c+d}{a+b}+\frac{d+a}{b+c}\)
A frac{frac{3}{4}-frac{3}{11}+frac{3}{13}}{frac{5}{4}-frac{5}{11}+frac{5}{13}}+frac{frac{1}{2}-frac{1}{3}+frac{1}{4}}{frac{5}{4}-frac{5}{6}+frac{5}{8}}B frac{2^{12}.3^5-4^6.9^2}{left(2^2.3right)^6+8^4.3^5}-frac{5^{10}.7^3-25^5.49}{left(125.7right)^3+5^9.14^3}C frac{left(a^{2016}+b^{2016}right)^{2017}}{left(c^{2016}+d^{2016}right)^{2017}} frac{left(a^{2017}-b^{2017}right)^{2016}}{left(c^{2017}-d^{2017}right)^{2016}}
Đọc tiếp
A = \(\frac{\frac{3}{4}-\frac{3}{11}+\frac{3}{13}}{\frac{5}{4}-\frac{5}{11}+\frac{5}{13}}+\frac{\frac{1}{2}-\frac{1}{3}+\frac{1}{4}}{\frac{5}{4}-\frac{5}{6}+\frac{5}{8}}\)
B = \(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^5.49}{\left(125.7\right)^3+5^9.14^3}\)
C = \(\frac{\left(a^{2016}+b^{2016}\right)^{2017}}{\left(c^{2016}+d^{2016}\right)^{2017}}\)= \(\frac{\left(a^{2017}-b^{2017}\right)^{2016}}{\left(c^{2017}-d^{2017}\right)^{2016}}\)
Cho a,b,c đôi 1 khác nhau
Tính: \(\frac{ab}{\left(b-c\right)\left(c-a\right)}\) . \(\frac{bc}{\left(c-a\right)\left(a-b\right)}\) . \(\frac{ca}{\left(a-b\right)\left(b-c\right)}\)