\(\frac{9+x}{13-x}=\frac{5}{6}\)
=> ( 9 + x ) .6 = ( 13 - x ) .5
=> 9.6 + 6x = 13.5 - 5x
=> 54 + 6x = 65 - 5x
=> 6x + 5x = 65 - 54
=> 11x = 11
=> x = 1
Tìm x \(\in\) Z
\(\frac{1}{-2}+\frac{1}{+}+\frac{-6}{9}\le x\le\left(\frac{1}{4}+\frac{-5}{13}\right)+\left(\frac{3}{6}+\frac{8}{-13}+\frac{9}{12}\right)\)
tìm x
a) \(x-\left[\frac{13}{18}x-\frac{24}{108}\right]=\left(\frac{-2}{3}\right)^2\)
b) \(3-7\frac{7}{12}< x< -\frac{5}{9}:\left(\frac{5}{9}-\frac{1}{6}\right)\)
tìm x biết:
a,\(7,5x:\left(9-6\frac{13}{21}\right)=2\frac{13}{25}\)
b,\(\frac{\left(1,16-x\right)\cdot5,25}{\left(10\frac{5}{9}-7\frac{1}{4}\right)\cdot2\frac{2}{17}}\)=75%
B=\(\frac{5}{9}x\frac{7}{13}+\frac{5}{9}x\frac{9}{13}-\frac{5}{9}x\frac{3}{13}\)
bài 1 tìm x biết
a, x=\(\frac{1}{36}+\frac{-3}{4}\)
b,x=\(\frac{2}{5}+\frac{1}{4}\)
c, x=\(\frac{1}{12}+\frac{3}{4}+\frac{-2}{9}\)
d, x,=\(\frac{1}{13}+\frac{-13}{26}\)
e, \(\frac{x}{15}=\frac{5}{6}+\frac{-4}{5}\)
1. Thực hiện phép tính :
\(\frac{-4}{9}.\frac{6}{13}+7\frac{4}{9}-\frac{4}{9}:\frac{13}{7}-5\frac{4}{9}-2\)2
2.Tìm x trong trường hợp sau :
x thuộc Z, 1 < (hoặc bằng) \(\frac{x}{5}\) < 0
Mọi người giúp mình nhé :D Nhớ ghi cách làm nữa nha rồi mình tick cho ;P
1. Tính:
a. \(75\%-1\frac{1}{2}.\frac{4}{3}+1,5:\frac{-9}{4}-\left(-\frac{1}{2}\right)^2\)
b. \(\frac{-4}{9}.\frac{6}{13}+7\frac{4}{9}-\frac{4}{9}:\frac{13}{7}-5\frac{4}{9}-2\)
2. Tìm x, biết:
a. \(x\in Z,-1\le\frac{x}{5}< 0\)
*làm nhanh nha, mk cần gấp lắm
Tìm x, biết: \(\frac{x+2}{17}+\frac{x+4}{15}+\frac{x+6}{13}=\frac{x+8}{11}+\frac{x+10}{9}+\frac{x+12}{7}\)
tìm biết :
\(\frac{x+2}{17}+\frac{x+14}{15}+\frac{x+6}{13}=\frac{x+8}{11}+\frac{x+10}{9}\frac{x+12}{7}\)
