Question

\(\frac{9}{10}-\left(\frac{2}{5}+\frac{3}{10}\right)+\frac{7}{20}=?\)

Answer 1

\(=\frac{9}{10}-\frac{7}{10}+\frac{7}{20}=\frac{2}{10}+\frac{7}{20}=\frac{4}{20}+\frac{7}{20}=\frac{11}{20}\)

Answer 2

\(\frac{9}{10}-\left(\frac{2}{5}+\frac{3}{10}\right)+\frac{7}{20}=\frac{9}{10}-\frac{7}{10}+\frac{7}{20}=\frac{2}{10}+\frac{7}{20}=\frac{4+7}{20}=\frac{11}{20}\)

Answer 3

\(\frac{9}{10}-\left(\frac{2}{5}+\frac{3}{10}\right)+\frac{7}{20}=\frac{9}{10}-\frac{7}{10}+\frac{7}{20}=\frac{1}{5}+\frac{7}{20}=\frac{11}{20}\)

Answer 4

trả lời:

9/10-(2/5+3/10)+7/20

=9/10-7/10+7/20

=2/10+7/20

=4/20+7/20

=11/20

Chúc Miyuki học tốt^^