\(\frac{7.8^3-5.2^{10}}{\left(-16\right)^2}\)\(=\frac{7.512-5.1024}{\left(-256\right)}\)\(=\frac{3583-5120}{\left(-256\right)}\)\(=\frac{1537}{256}\)
Mình học hơi kém nếu sai mong mn đừng gạch đá .
\(\frac{7.8^3-5.2^{10}}{\left(-16\right)^2}\)\(=\frac{7.512-5.1024}{\left(-256\right)}\)\(=\frac{3583-5120}{\left(-256\right)}\)\(=\frac{1537}{256}\)
Mình học hơi kém nếu sai mong mn đừng gạch đá .
Tính B = \(\frac{7.8^3-5.2^{10}}{\left(-16\right)^2}\)+ (2,15 *4 + 2,12 *5 )\(^0\)
B=\(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)
C=\(\frac{2^{13}.4^{11}-16^9}{\left(3.2^{17}\right)^2}\)
D=\(\frac{4^7.2^8}{3.2^{15}.16^2-5.2^2.\left(2^{10}\right)^2}\)
1) 1.2.3...9 - 1.2.3...8 - 1.2.3...7.82
2) \(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
3)13 - 12 + 11 + 10 - 9 + 8 - 7 - 6 + 5 -4 +3 +2 -1
Tính tổng
\(\frac{4^7.2^8}{3.2^{15}.16^2-5.2^2.\left(2^{10}\right)^2}\)
thực hiện các phép tính sau một cách hợp lí:
a,\(\left(10^2+11^2+12^2\right):\left(13^2+14^2\right)\)
b,\(1.2.3...9-1.2.3...8-1.2.3...7.8^2\)
c,\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
d,1152-(374+1152)+(-65+374)
e,13-12+11+10-9+8-7-6+5-4+3-2-1
Rút gọn Phân số:
1, \(\frac{7.25^{14}.125^3-3.625^9.5}{2.4^2.\left(5^2\right)^{18}}\)
2, \(\frac{4^7.2^8}{3.2^{15}.16^2-5.2.\left(2^{10}\right)^2}\)
a, \(\left(10^2+11^2+12^2\right)\div\left(13^2+14^2\right)\\ \)
b,\(1.2.3.....9-1.2.3....8-1.2.3.....7.8^2\)
c, \(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
d, \(1152-\left(374+1152\right)+\left(-65+374\right)\)
\(\frac{9^{3.}7+27^2.3}{3^4.2+9^2.5^2}\)\(\frac{5.2^{11}.4^{11}-16^9}{\left(3.2^{17}\right)^2}\);\(\frac{\left(-3\right)^5.9^5.6^3.\left(-4\right)^4}{18^9}\);\(\frac{-2^4.5^2}{-8.9.119+36.78}\)
A = \(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)
B = 3.{ 5 . [ ( 5^2 + 2^3 ) : 11 ] -16} + 2015
C = \(\left(1+\frac{1}{1.3}\right).\left(1+\frac{1}{2.4}\right).\left(1+\frac{1}{3.5}\right).....\left(1+\frac{1}{2014.2016}\right)\)