36 + [16 - 3 * (x + 2)] = 36
13 * (x + 2) = 36 - 36
13 * (x + 2) = 0
x + 2 = 0 : 13
x + 2 = 0
x = 0 - 2
x = -2
36+[16-3*(x+2)]=36
[16-3*(x-2)] =36-36
16-3*(x-2) =0
13*(x-2) =0
(x-2) =0:13
(x-2) =0
x =0+2
x =2
suy ra x=2
nho kich minh nhe!!!!!!!!!!!!
36+[16-3*(x+2)]=36
16-3*(x+2)=36-36
16-3*(x+2)=0
3*(x+2)=16-0=16
x+2=16/3
x=16/3-2
x=10/3
36+[16-3x(X+2)]=36
16-3x(X+2)=36-36
16-3x(X+2)=0
3x(X+2)=16-0
3x(X+2)=16
X+2=16:3
X+2=16/3
X=16/3-2
X=16/3-6/3
X=10/3