Question

\(\frac{75}{100}-1\frac{1}{2}+0,5:\frac{5}{12}-\left(-\frac{1}{2}\right)^3\)

Answer 1

\(=\frac{75}{100}-\frac{3}{2}+\frac{1}{2}:\frac{5}{12}-\left(-\frac{1}{3}\right)^2\)

\(=\frac{3}{4}-\frac{3}{2}+\frac{6}{5}-\frac{1}{9}\)

\(=\frac{-3}{4}+\frac{6}{5}-\frac{1}{9}\)

\(=\frac{9}{20}-\frac{1}{9}\)

\(=\frac{61}{180}\)

Answer 2

\(\frac{75}{100}-1\frac{1}{2}+0,5:\frac{5}{12}-\left(-\frac{1}{2}\right)^3\)

= \(\frac{3}{4}-\frac{3}{2}+\frac{1}{2}:\frac{5}{12}-\frac{-1}{8}\)

= \(\frac{3}{4}-\frac{6}{4}+\frac{1}{2}\cdot\frac{12}{5}-\frac{-1}{8}\)

= \(-\frac{3}{4}+\frac{6}{5}-\frac{-1}{8}=\frac{-30}{40}+\frac{48}{40}+\frac{-6}{40}=\frac{12}{40}=\frac{3}{10}\)

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Answer 3

= \(\frac{75}{100}-\frac{3}{2}+\frac{6}{5}-"-\frac{1}{2}"^3=\frac{75}{100}-\frac{3}{2}+\frac{6}{5}-\frac{53}{40}=\)\(-\frac{3}{4}+-\frac{1}{8}=-\frac{1}{4}\)

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