Question

\(\frac{7-x}{2009}+\frac{5-x}{2011}+\frac{3-x}{2013}=-3\)

giải pt

Answer 1

ta có pt trên <=> \(\frac{7-x}{2009}+1+\frac{5-x}{2011}+1+\frac{3-x}{2013}=0\)

<=> \(\frac{7-x}{2009}+\frac{2009}{2009}+\frac{5-x}{2011}+\frac{2011}{2011}+\frac{3-x}{2013}+\frac{2013}{2013}=0\)

<=> \(\frac{2016-x}{2009}+\frac{2016-x}{2011}+\frac{2016-x}{2013}=0\)

<=> \(\left(2016-x\right)\left(\frac{1}{2009}+\frac{1}{2011}+\frac{1}{2013}\right)=0\)

do \(\frac{1}{2009}+\frac{1}{2011}+\frac{1}{2013}\) >0

=> 2016-x=0

=> x=2016