\(\frac{5x+2}{6}-\frac{8x-1}{3}=\frac{4x+2}{5}-5\)
\(\Leftrightarrow\)\(\frac{5\left(5x+2\right)}{30}-\frac{10\left(8x-1\right)}{30}=\frac{6\left(4x+2\right)}{30}-\frac{150}{30}\)
\(\Leftrightarrow\)\(5\left(5x+2\right)-10\left(8x-1\right)=6\left(4x+2\right)-150\)
\(\Leftrightarrow\)\(25x+10-80x+80=24x+12-150\)
\(\Leftrightarrow\)\(79x=240\)
\(\Leftrightarrow\)\(x=\frac{240}{79}\)
ủa bạn ơi, ở hàng thứ 4 là -10(8x - 1) = -80x + 10 chứ???
bài kia của mk nhầm chút nhé, mk làm lại, m.n cho mk xin lỗi ạ
\(\frac{5x+2}{6}-\frac{8x-1}{3}=\frac{4x+2}{5}-5\)
\(\Leftrightarrow\)\(\frac{5\left(5x+2\right)}{30}-\frac{10\left(8x-1\right)}{30}=\frac{6\left(4x+2\right)}{30}-\frac{150}{30}\)
\(\Leftrightarrow\)\(5\left(5x+2\right)-10\left(8x-1\right)=6\left(4x+2\right)-150\)
\(\Leftrightarrow\)\(25x+10-80x+10=24x+12-150\)
\(\Leftrightarrow\)\(79x=158\)
\(\Leftrightarrow\)\(x=2\)
