\(\frac{5}{x+1}-\frac{10}{x-x^2-1}-\frac{15}{x^3+1}\)
\(\frac{6}{5x-20}-\frac{x-5}{x^2-8x+16}\)
\(\frac{X^2}{x^2-x}-\frac{x^2}{x+1}-\frac{2}{x^2-1}\)
\(\frac{1}{x^3-1}+\frac{1}{1-x}+\frac{1}{x^2+x+1}\)
\(\frac{x}{x-1}-\frac{2}{x+1}-\frac{2}{x^2-1}\)
Mọi người giúp mình giải nhx phép tính này nha 😁 Cảm ơn trước nhé 😇
Giải các phương trình sau:
a) \(\frac{x+1}{x-2}+\frac{x-1}{x+2}=\frac{2.\left(x^2+2\right)}{x^2-4}\)
b) \(\frac{5-x}{4x^2-8x}-\frac{1}{8x-16}=\frac{x-1}{2x^2-4x}-\frac{7}{8x}\)
c) \(\frac{13}{2x^2+x-21}+\frac{1}{2x+7}=\frac{6}{x^2-9}\)
d)\(\frac{x-3}{x-2}+\frac{x-2}{x-4}=\frac{11}{3}\)
e) \(\frac{2.x}{x-1}=\frac{5.\left(x-1\right)}{x+1}\)
f) \(\frac{1}{x^2-2.x+2}+\frac{2}{x^2-2.x+3}=\frac{6}{x^2-2.x+4}\)
Ai giúp mình được bài nào thì giúp nha. Cám ơn
Giải phương trình sau:
a) \(\frac{4}{-25x^2+20x-3}=\frac{3}{5x-1}-\frac{2}{5x-3}\)
b) \(\frac{1}{x^2-3x+2}+\frac{1}{x^2-5x+6}-\frac{2}{x^2-4x+3}\)
c)\(\frac{x-1}{2x^2-4x}-\frac{7}{8x}=\frac{5-x}{4x^2-8x}-\frac{1}{8x-16}\)
d)\(\frac{1}{x^2+9x+20}+\frac{1}{x^2+11x+30}+\frac{1}{x^2+13x+42}=\frac{1}{18}\)
Giải các phương trình sau:
\(\frac{3}{4x-20}-\frac{15}{2x^2-50}+\frac{7}{6x+30}=0\)
\(\frac{8x^2}{3-12x^2}+\frac{1+8x}{4+8x}=\frac{-2x}{3-6x}\)
\(\frac{1}{x^2-2x+1}+\frac{1}{x^2+2x=1}=\frac{2}{x^2-1}\)
\(\frac{1}{x^2+1}+\frac{1}{x^2+3x+2}+\frac{1}{x^2+5x+6}+\frac{1}{x^2+7x+12}=\frac{4}{5}\)
Giải các phương trình:
\(a,\frac{1}{x-1}-\frac{3x^2}{x^3-1}=\frac{2x}{x^2+x+1}\)
\(b,\frac{1}{x^2-5x+6}+\frac{2}{x^2-8x+15}+\frac{3}{x^2-13x+40}=\frac{6}{5}\)
Giải các phương trình,bất phương trình:
c,\(\frac{\left(x-2\right)^2}{3}-\frac{\left(2x-3\right)\left(2x+3\right)}{8}+\frac{\left(x-4\right)^2}{6}=0\)
d,\(\frac{4}{-25x^2+20x-3}=\frac{3}{5x-1}-\frac{2}{5x-3}\)
e,\(\frac{1}{x^2-3x+2}+\frac{1}{x^2-5x+6}-\frac{2}{x^2-4x+3}=0\)
g,\(\frac{x-1}{2x^2-4x}-\frac{7}{8x}=\frac{5-x}{4x^2-8x}-\frac{1}{8x-16}\)
h,\(\frac{1}{x^2+9x+20}+\frac{1}{x^2+11x+30}+\frac{1}{x^2+13x+42}=\frac{1}{18}\)
i,\(\left(2x-5\right)^2-\left(x+2\right)^2=0\)
k,\(\left(3x^2+10x-8\right)^2=\left(5x^2-2x+10\right)^2\)
l,\(\left(x^2-2x+1\right)-4=0\)
m,\(4x^2+4x++1=x^2\)
Xin đáy ai giúp mình đi
Giải phương trình:
1.\(\frac{x-5}{x-5}+\frac{x-6}{x-5}+\frac{x-7}{x-5}+...+\frac{1}{x-5}=4\left(x\in N\right)\)
2.\(\frac{1}{x^2+3x+2}+\frac{1}{x^2+5x+6}+\frac{1}{x^2+7x+12}+...+\frac{1}{x^2+15x+56}=\frac{1}{14}\)
3.\(\left(1+\frac{1}{1.3}\right)\left(1+\frac{1}{2.4}\right)\left(1+\frac{1}{3.5}\right)...\left(1+\frac{1}{x\left(x+2\right)}\right)=\frac{31}{16}\left(x\in N\right)\)
4.\(8\left(x^2+\frac{1}{x^2}\right)-34\left(x+\frac{1}{x}\right)+51=0\)
5.\(6x^4-5x^3-38x^2-5x+6=0\)
GIÚP MÌNH NHÉ!!
Thực hiện phép tính:
a) \(\frac{x+3}{x}-\frac{x}{x-3}+\frac{9}{x^2-3x}\)
b) \(\frac{1}{3x-2}-\frac{4}{3x+2}-\frac{-10x+8}{9x^2-4}\)
c) \(\frac{4a^2-3a+5}{a^3-1}-\frac{1-2a}{a^2+a+1}-\frac{6}{a-1}\)
d) \(\frac{x+9y}{x^2-9y^2}-\frac{3y}{x^2+3xy}\)
e) \(\frac{3x+2}{x^2-2x+1}-\frac{6}{x^2-1}-\frac{3x-2}{x^2+2x+1}\)
f) \(\frac{5}{a+1}-\frac{10}{a-\left(a^2+1\right)}-\frac{15}{a^3+1}\)
giải phương trình sau:
a. \(\frac{6x+1}{x^2-7x+10} +\frac{5}{x-2}=\frac{3}{x-5}\)
b.\(\frac{2}{x^2-4}-\frac{x-1}{x\left(x-2\right)}+\frac{x-4}{x\left(x+2\right)}=0\)
c. \(\frac{1}{3-x}-\frac{1}{x+1}=\frac{x}{x-3}-\frac{\left(x-1\right)^2}{x^2-2x-3}\)
d.\(\frac{1}{x-2}-\frac{6}{x+3}=\frac{5}{6-x^2-x}\)
e.\(\frac{2}{x+2}-\frac{2x^2+16}{x^3+8}=\frac{5}{x^2-2x-3}\)
f. \(\frac{x+1}{x^2+x+1}-\frac{x-1}{x^2-x+1}=\frac{2\left(x+2\right)^2}{x^6-1}\)
mấy chế ai biết giải thì giải dùm mik mấy bài nè vs.
Giải phương trình:
1) \(\frac{1}{x^2+3x+2}+\frac{1}{x^2+5x+6}+\frac{1}{x^2+7x+12}=\frac{1}{6}\)
2) \(\frac{1}{x^2-6x+8}+\frac{1}{x^2-10x+24}+\frac{1}{x^2-14x+48}=\frac{1}{9}\)
3) \(\frac{1}{x^2-3x+3}+\frac{2}{x^2-3x+4}=\frac{6}{x^2-3x+5}\)
4) \(\frac{6}{\left(x+1\right)\left(x+2\right)}+\frac{8}{\left(x-1\right)\left(x+4\right)}=1\)
5) \(4\left(x^3+\frac{1}{x^3}\right)=13\left(x+\frac{1}{x}\right)\)
6) \(\frac{4x}{4x^2-8x+7}+\frac{3x}{4x^2-10x+7}=1\)
7) \(\frac{x^2-3x+5}{x^2-4x+5}-\frac{x^2-5x+5}{x^2-6x+5}=\frac{-1}{4}\)
8) \(x\frac{8-x}{x-1}.\left(x-\frac{8-x}{x-1}\right)=15\)
