Question

\(\frac{4x}{3y}\)=\(\frac{3}{4}\)và 8x+9y=-30

Answer 1

\(\frac{4x}{3y}=\frac{3}{4}\Rightarrow\frac{4x}{3}=\frac{3y}{4}\Rightarrow\frac{8x}{6}=\frac{9y}{12}=\frac{8x+9y}{18}=-\frac{30}{18}=-\frac{5}{3}\)

\(\Rightarrow\frac{8x}{6}=\frac{-5}{3}\Rightarrow x=-\frac{5}{3}.\frac{6}{8}=-\frac{5}{4}\)

\(\Rightarrow\frac{9y}{12}=-\frac{5}{3}\Rightarrow y=-\frac{5}{3}.\frac{12}{9}=-\frac{20}{9}\)