\(\frac{4^6.3^4.9^5}{6^{12}}=\frac{\left(2^2\right)^6.3^4.\left(3^2\right)^5}{\left(2.3\right)^{12}}=\frac{2^{12}.3^{14}}{2^{12}.3^{12}}=3^2=9\)
=\(\frac{\left(2^2\right)^6.3^4.\left(3^2\right)^5}{\left(2\cdot3\right)^{12}}=\frac{2^{12}.3^4.3^{10}}{2^{12}.3^{12}}=\frac{3^{14}}{3^{12}}=3^2=9\)
\(\frac{4^6.3^4.9^5}{6^{12}}=\frac{2^6.2^2.2^4.3^4.9^5}{6^4.6^8}=\frac{2^8.6^4.9^5}{6^4.6^8}=\frac{2^8.9^5}{2^8.3^8}=\frac{3^{10}}{3^8}=3^2=9\)
ta có:
\(\frac{4^6.3^4.9^5}{6^{12}}=\frac{\left(2^2\right)^6.3^4.\left(3^2\right)^5}{6^{12}}\)
=\(\frac{2^{12}.3^4.3^{10}}{6^{12}}=\frac{2^{12}.3^4.3^8.3^2}{6^{12}}\)
=\(\frac{2^{12}.3^{12}.3^2}{6^{12}}=\frac{\left(2.3\right)^{12}.9}{6^{12}}\)
=\(\frac{6^{12}.9}{6^{12}}=9\)