-42/32.(15/8-16/41)+15/8.(41/32.8/3)
=-42/32.487/328+15/8.41/12
=-10227/5248+205/32
=23393/5248
-42/32.(15/8-16/41)+15/8.(41/32.8/3)
=-42/32.487/328+15/8.41/12
=-10227/5248+205/32
=23393/5248
\(\frac{31}{23}-\left(\frac{7}{32}+\frac{8}{23}\right)+\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)
so sánh\(A=\frac{31}{13}-\left(\frac{7}{32}+\frac{8}{2}\right)vaB=\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)
so sánh: A= \(\frac{31}{23}-\left[\frac{7}{32}+\frac{8}{2}\right]\) và B=\(\left[\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right]-\left[\frac{79}{67}-\frac{28}{41}\right]\)
So sánh:
A = \(\frac{31}{23}-\left(\frac{7}{32}+\frac{8}{2}\right)\)và B = \(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)
1) Tính hợp lý
a)\(\frac{31}{23}-\left(\frac{7}{32}+\frac{8}{32}\right)\)
b)\(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)
c)\(\frac{38}{45}-\left(\frac{8}{45}-\frac{17}{51}-\frac{3}{11}\right)\)
d)\(\left(\frac{17}{28}+\frac{18}{29}-\frac{19}{30}-\frac{30}{31}\right).\left(-\frac{5}{12}+\frac{1}{4}+\frac{1}{6}\right)\)
\(SO\)\(SÁNH\)
\(A=\frac{31}{23}-\left(\frac{7}{32}+\frac{8}{2}\right)\)VÀ \(B=\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)
Tính nhanh
1, \(10\frac{5}{4}-4\frac{9}{14}-6\frac{5}{7}+\frac{7}{3}\)
2, \(\frac{29}{32}\left(\frac{41}{36}-\frac{32}{58}\right)-\frac{41}{36}\left(\frac{29}{32}+\frac{18}{41}\right)\)
a)\(\frac{-1}{2}+\frac{-1}{3}+\frac{-5}{4}\) b)\(4\frac{1}{3}.\left(\frac{1}{6}-\frac{1}{2}\right)\)
c)\(\frac{17}{7}+\frac{15}{4}-\frac{20}{4}+\frac{1}{4}-3\) d)\(\frac{29}{32}\left(\frac{41}{36}-\frac{32}{58}\right)-\frac{41}{36}\left(\frac{29}{32}+\frac{18}{41}\right)\)
Tính bằng cách hợp lý nhất:
a, \(\frac{31}{23}-\left(\frac{7}{32}+\frac{8}{23}\right)\)
b, \(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)\)
c, \(\frac{38}{45}-\left(\frac{8}{45}-\frac{17}{51}-\frac{3}{11}\right)\)
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