=\(\frac{3x}{2,7}=\frac{1}{9}\)
\(\frac{10\left(3x\right)}{27}=\frac{1}{9}\)
\(\left(30x\right).9=27\)
\(30x=3\)
\(x=\frac{1}{10}\)
(Mình ko chép đề nha )\(3x.2\frac{1}{4}=\frac{1}{4}.2,7\)
\(\Rightarrow3x.\frac{9}{4}=\frac{1}{4}.\frac{27}{10}\)
\(\Rightarrow3x.\frac{9}{4}=\frac{27}{40}\)
\(\Rightarrow3x=\frac{3}{10}\)
\(\Rightarrow x=\frac{1}{10}\)
_Học tốt nha_
tìm x biết
a,\(\left|2x+\frac{3}{4}\right|=\frac{1}{2}\)
b,\(\frac{3x}{2,7}=\frac{\frac{1}{4}}{2\frac{1}{4}}\)
c,\(\left|x-1\right|+4=6\)
d, \(\frac{x}{3}=\frac{y}{5}\) và y-x=24
e, \(\left(x^2-3\right)^2=16\)
f, \(\frac{3}{4}+\frac{2}{5}x=\frac{29}{60}\),
g, \(\left(-\frac{1}{3}\right)^3.x=\frac{1}{81}\)
k,\(\frac{3}{4}-\frac{2}{5}x=\frac{29}{60}\)
l,\(\frac{3}{5}x-\frac{1}{2}=-\frac{1}{7}\)
\(a,\frac{x}{-27}=-\frac{3}{x}\)
b,\(3x\)\(:\)\(2,7=\frac{1}{3}:2\frac{1}{3}\)
BÀI 1
1 ) \(\frac{23}{7}\). ( 10,5 ) - \(\frac{23}{7}\). \(\frac{7}{2}\)
2) 35 : 34 + 26 + 24
3) _\(\sqrt{\frac{81}{16}}\)
BÀI 2
1) 0,5 . x + 0,15 = 0,35
2) |2x+\(\frac{3}{4}\) | = 0,5
3) 3x : 2,7 = \(\frac{1}{4}\) : \(\frac{9}{4}\)
MK CAN GAP
\(4.\left(x-\frac{3}{4}\right)-\frac{1}{5}.\left(3x+1\right)=6\frac{1}{2}-\frac{3}{4}\)
1 Tìm x:
( \(3x-2\frac{1}{3}\)):( \(3\frac{1}{4}-5\frac{2}{3}+1\frac{4}{5}\)) = \(2-1\frac{1}{3}x\)
2. Tìm x:
\(\frac{x+\frac{2\left(3-x\right)}{5}}{14}-\frac{5x-4\left(x-1\right)}{24}=\frac{7x+2+\frac{9-3x}{5}}{12}+\frac{2}{3}\)
3. Tìm x:
\(\left(1+3x\right)^2-3x\left(2x+6\right)=\left(4-3x\right)\left(x+3\right)-\left(2x-1\right)^2\)
Tìm x
\(\frac{1}{10}+\frac{1}{40}+\frac{1}{88}+...+\frac{1}{\left(3x+2\right).\left(3x+5\right)}=\frac{4}{25}\)
3x - 1 = \(\frac{2.2017}{1+\frac{1}{1+2}+\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+...+\frac{1}{1+2+3+4+...+2014}}\)
Bạn nào gửi bài trước mk tick cho nha
Bài 1 Tìm x
a) 3,2.x +(1,2).x+2,7= -4,9
b) (-5,6).x+2,9.x-3,86= -9,8
Bài 2
A = \(-5,13:\left(\frac{145}{28}-\frac{17}{9}.1,25+1\frac{16}{63}\right)\)
B= \(\left(3\frac{1}{3}.1,9+19,5:4\frac{1}{3}\right).\left(\frac{62}{75}-\frac{4}{25}\right)\)
giuk mik tickcho nhé
\(\frac{3}{2}x-\frac{2}{5}=\frac{1}{3}x-\frac{1}{4}\)
\(3x-\frac{5}{3}=x-\frac{1}{4}\)
\(3\left(x-\frac{1}{2}\right)-3\left(x-\frac{1}{3}\right)=x\)
