Question

\(\frac{3x+2}{5x+7}=\frac{3x-1}{5x+1}\)
Tìm x , giúp mình nhé 
 

Answer 1

=>(3x+2)(5x+1)=(5x+7)(3x-1)

(3x)(5x+1)+2(5x+1)=(5x)(3x-1)+7(3x-1)

15x²+3x+10x+2=15x²-5x+21x-7

(15x²-15x²)+(3x+10x+5x-21x)=-7-2

0-3x=-9

-3x=-9

x=(-9)/(-3)

x=3

Answer 2

\(\frac{3x+2}{5x+7}\)=\(\frac{3x-1}{5x+1}\)

\(\Rightarrow\)\(\frac{3x+2}{3x-1}\)= \(\frac{5x+7}{5x+1}\)\(\Rightarrow\)1+\(\frac{3}{3x-1}\)=1+\(\frac{6}{5x+1}\)

\(\Rightarrow\)\(\frac{3}{3x-1}\)= \(\frac{6}{5x+1}\)\(\Rightarrow\)3.(5x+1) = 6.(3x-1)

\(\Rightarrow\)15x+3 = 18x -6

\(\Rightarrow\)3x = 6 +3

\(\Rightarrow\)x =3